44-2x=x^2-20x+100

Solution for 44-2x=x^2-20x+100 equation:

44-2x=x^2-20x+100

We move all terms to the left:

44-2x-(x^2-20x+100)=0

We get rid of parentheses

-x^2-2x+20x-100+44=0

We add all the numbers together, and all the variables

-1x^2+18x-56=0

a = -1; b = 18; c = -56;
Δ = b2-4ac
Δ = 182-4·(-1)·(-56)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-10}{2*-1}=\frac{-28}{-2}
=+14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+10}{2*-1}=\frac{-8}{-2}
=+4
$